Question

What is the slope of a line that pass through the points (3,-2) and (5,-2)?

Answer 1

`(\stackrel{x_1}{3}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{-2}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-2}-\stackrel{y1}{(-2)}}}{\underset{\textit{\large run}} {\underset{x_2}{5}-\underset{x_1}{3}}} \implies \cfrac{-2 +2}{2} \implies \cfrac{ 0 }{ 2 } \implies \text{\LARGE 0}`

Answer 2

slope = 0

Explanation:

calculate the slope m using the slope formula

m =
`(y_(2)-y_(1) )/(x_(2)-x_(1) )`

with (x₁, y₁ ) = (3, - 2 ) and (x₂, y₂ ) = (5, - 2 )

m =
`(-2-(-2))/(5-3)` =
`(-2+2)/(2)` =
`(0)/(2)` = 0