Question

Reagan went to the playground. She played on the swings for 24 minutes and went on the slide for 13 minutes. It was 4:28 P.M. when Reagan left the playground. What time was it when Reagan arrived at the playground?

Answer 1

If she played on the swings for 24 minutes and on the slide for 13, then she was at the playground for 37 minutes.

If she left the playground at 4:28, then you want to subtract 37 minutes from 4:28.

4:28 - :37 = 3:51.

She arrived at the playground at 3:51

Explanation:

Hope it helps! =D

Answer 2

3:51 p.m.

Explanation:

Add the two amounts of time:

24 minutes + 13 minutes = 37 minutes

She was at the park for 37 minutes. She arrived at the park 37 minutes before 4:28 p.m.

Now we subtract 37 minutes from 4:28 p.m.

Remember that 1 hour = 60 minutes, so when you borrow 1 hour to do the subtraction, you add 60 minutes to the minutes of the time of day.

Borrow 1 hour from 4 hours as 60 minutes. You end up with 3 hours. Then add the 60 minutes to the 28 minutes to get 88 minutes.

4:28 p.m. is the same as 3:88 p.m.

4:28 p.m. 3:88 p.m.

- 0:37 -----> - 0:37

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3:51 p.m.

Answer: 3:51 p.m.