Answer: The equation of a line in the form y = mx + b can be written as y - mx - b = 0. So we can rewrite the equation of the line as 2y - 3x + 5 = 0. This means that the slope of the line is -3/2.
The slope of a line perpendicular to this line would be the negative reciprocal of -3/2, which is 2/3. Let's call the point M (x, y). We know that the line passing through (2, 6) has a slope of 2/3. So we can write the equation of this line as:
y - (2/3)x - b = 0
Substituting the point (2, 6) into this equation, we get:
6 - (2/3)(2) - b = 0
b = 4
So the equation of the line passing through (2, 6) is:
y - (2/3)x - 4 = 0
To find the coordinates of point M, we need to find the point where these two lines intersect. Setting the two equations equal to each other and solving for x and y, we get:
2y - 3x + 5 = y - (2/3)x - 4
5 - 2y = y - (5/3)x + 4
(5/3)x = 3 - y
x = (3 - y) * (3/5)
Substituting this expression for x into one of the original equations, we can solve for y:
2y - 3((3 - y) * (3/5)) + 5 = 0
2y - (9 - 3y)(3/5) + 5 = 0
(10/5)y - (9/5) + 5 = 0
y = (9/5) + (5/5)
y = 2
Substituting this value for y back into the expression for x, we get:
x = (3 - 2) * (3/5)
x = 1
So the coordinates of point M are (1, 2).
Explanation: