Answer: To find an equation of the line that passes through the point (-5,-6) and is parallel to the line 4x−5y=35, we can use the fact that two lines are parallel if and only if they have the same slope.
The slope of the line 4x−5y=35 is -4/5. Therefore, we can find an equation of the line that passes through (-5,-6) and is parallel to 4x−5y=35 by using the slope-intercept form of a linear equation, y = mx + b, where m is the slope of the line and b is the y-intercept (the point where the line crosses the y-axis).
Substituting the values into the slope-intercept form, we get:
y = (-4/5)x + b
To find the value of b, we can substitute the coordinates of the point (-5,-6) into the equation:
-6 = (-4/5)(-5) + b
-6 = 8/5 + b
-6 - 8/5 = b
-24/5 = b
Therefore, the equation of the line that passes through the point (-5,-6) and is parallel to the line 4x−5y=35 is:
y = (-4/5)x - 24/5
This can also be written as:
y = -4/5x - 24/5
Explanation: