Answer: To determine the games in which a person who buys a ticket for each game every day for the next 400 days could expect to lose less than a total of $200, we need to find the games in which the probability of winning is greater than the probability of losing.
Since the tickets for all of the games cost $2 per ticket, the probability of winning any given game is equal to the prize money divided by the ticket cost. For example, if the prize money for a game is $10, the probability of winning is $10/$2 = 1/2.
If the probability of winning a game is greater than the probability of losing, the expected value of the game is positive, which means that the person can expect to win more than they lose over time. On the other hand, if the probability of winning is less than the probability of losing, the expected value of the game is negative, which means that the person can expect to lose more than they win over time.
Therefore, to determine which games the person could expect to lose less than $200 in total, we need to find the games in which the prize money is greater than $2 per ticket.
Explanation: