Question

Patel is solving 8x2 + 16x + 3 = 0. Which steps could he use to solve the quadratic equation? Select three options. 8(x2 + 2x + 1) = –3 + 8 x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot x = –1 Plus or minus StartRoot StartFraction 4 Over 8 EndFraction EndRoot 8(x2 + 2x + 1) = 3 + 1 8(x2 + 2x) = –3

Answer 1

Answer: To solve the quadratic equation 8x^2 + 16x + 3 = 0, Patel could use the following steps:

Divide both sides of the equation by 8 to obtain x^2 + 2x + 3/8 = 0.

Rewrite the equation in the form (x + a)^2 = b by completing the square: x^2 + 2x + (1/2)^2 = (1/2)^2 - (3/8).

Rewrite the equation as (x + a)^2 - b = 0. In this case, a = 1/2 and b = -3/8.

Use the quadratic formula to solve for x:

x = (-1/2) +/- sqrt((1/2)^2 - (-3/8))

= (-1/2) +/- sqrt(5/8)

= (-1/2) +/- sqrt(40/64)

= (-1/2) +/- sqrt(10/16)

= (-1/2) +/- (5/8)

= -1 +/- 5/8

= -1 + 5/8 or -1 - 5/8

= -7/8 or 1/8

Therefore, the solutions to the quadratic equation are x = -7/8 or x = 1/8.

Explanation: