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Inga is solving 2x2 + 12x – 3 = 0. Which steps could she use to solve the quadratic equation? Select three options. 2(x2 + 6x + 9) = 3 + 18 2(x2 + 6x) = –3 2(x2 + 6x) = 3 x + 3 = Plus or minus StartRoot StartFraction 21 Over 2 EndFraction EndRoot 2(x2 + 6x + 9) = –3 + 9

User Mutsu
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Answer: To solve a quadratic equation of the form ax^2 + bx + c = 0, there are several steps that Inga could use. Here are three options:

She could complete the square to rewrite the equation in the form (x + p)^2 = q.

She could use the quadratic formula: x = (-b +/- √(b^2 - 4ac)) / (2a).

She could factor the equation to rewrite it in the form (x + r)(x + s) = 0.

Option 1: Completing the square

To complete the square, Inga could add and subtract (b/2)^2 to the equation to get:

a(x^2 + bx + (b/2)^2) - (b/2)^2 = 0

Then, she could rewrite the equation in the form:

a(x + (b/2))^2 = (b/2)^2

Option 2: Using the quadratic formula

To use the quadratic formula, Inga could substitute the values of a, b, and c into the formula to get:

x = (-12 +/- √(12^2 - 4 * 2 * -3)) / (2 * 2)

= (-12 +/- √(144 + 24)) / 4

= (-

Explanation:

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