Question

A barefoot field-goal kicker imparts a speed of 22 m/s to a football initially at rest. If the football has a mass of 0.42 kg and the time of contact with the ball is 0.023 s, what is the magnitude of the force exerted by the ball on the kicker’s foot? Answer in units of N

Answer 1

Step-by-step explanation:

Mass of the football = 0.49 kg

Initial velocity of the ball ,u= 0 m/s

Final velocity of the ball ,v= 44 m/s

time of contact ,t = 0.028 seconds

First law of motion:

v=u+at

44 m/s=0+a\times 0.028 sec44m/s=0+a×0.028sec

a=1,571.42 m/s^2a=1,571.42m/s

2

force=mass\times acceleration=0.49 kg\times 1,571.42 m/s^2=769.99Nforce=mass×acceleration=0.49kg×1,571.42m/s

2

=769.99N

The magnitude of the force exerted by the ball on the kicker's foot is of 769.99 Newtons.