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5 votes
5 votes
How do you put
y = - (3)/(2) x + 3on a graph

User IceFire
by
3.1k points

1 Answer

16 votes
16 votes

The equation to graph is:


y=-(3)/(2)x+3

Let's break it down and see how can we EASILY graph this!!

The first point is to always put x = 0 and find the y-value. This way, we graph the y-intercept. Thus,


\begin{gathered} y=-(3)/(2)x+3 \\ y=-(3)/(2)(0)+3 \\ y=3 \end{gathered}

So, y-intercept is (0, 3).

Now, look at the slope, the constant before "x". It is -3/2.

The numerator is rise and denominator is run.

Thus, from the y-intercept, we move "-3" units "rise" (y-direction) and "2" units "run" (x-direction).

We will arrive at (2,0).

Then we can make this move again!

We will arrive at (4, -3).

That's it!!

We can now graph the 3 points found, draw a smooth line through these points and that's our line!!

The graph of the line is shown below:

How do you put y = - (3)/(2) x + 3on a graph-example-1
User Sean McMillan
by
3.0k points