Answer:
Since A, O and B are collinear,
i.e.,
∠
A
O
B
=
180
∘
or,
∠
A
O
D
+
∠
D
O
C
+
∠
B
O
C
=
180
∘
(
x
−
10
)
∘
+
(
4
x
−
25
)
∘
+
(
x
+
5
)
∘
=
180
∘
Or,
x
+
4
x
+
x
−
10
∘
−
25
∘
+
5
∘
=
180
∘
Or,
6
x
−
30
∘
=
180
∘
Or,
6
x
=
180
∘
+
30
∘
=
210
∘
Or,
x
=
210
∘
6
=
35
∘
∠
B
O
C
=
x
+
5
∘
=
35
∘
+
5
∘
=
40
∘