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An electric cord can be stretched to its elastic limit by a load of 3N. If a 350cm length of the cord is extended by a force of 0.5N, what will be the length of the cord when the stretching force is 2.5N? ​

1 Answer

4 votes

Answer:

359cm

Step-by-step explanation:

The change in length of the cord due to a stretching force of 0.5N is given by Hooke's law:

ΔL = k * ΔF

Where ΔL is the change in length, k is the spring constant and ΔF is the change in force.

Since the spring constant for the cord is 3N/cm, the change in length due to a stretching force of 0.5N is:

ΔL = (3N/cm) * (0.5N) = 1.5 cm

Since the cord is already 350cm long, the total length of the cord when the stretching force is 0.5N is 350cm + 1.5cm = 351.5cm.

To find the length of the cord when the stretching force is 2.5N, we can use the same formula:

ΔL = (3N/cm) * (2.5N) = 7.5 cm

The total length of the cord when the stretching force is 2.5N is therefore 351.5cm + 7.5cm = 359cm.

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