Question

How do you solve this? 11t-t^2=30

Answer 1

The solution set is {5, 6}.

Explanation:

11t-t^2=30

t^2 - 11t + 30 = 0

(t - 5)(t - 6) = 0

t = 5, 6.

Answer 2

t = 5, 6

Explanation:

Given the equation:

`\displaystyle{11t-t^2=30}`

First, arrange the expression in the standard quadratic form ax² + bx + c = 0

`\displaystyle{t^2-11t+30=0}`

Then factor the expression, find two numbers that add up which result in -11 and multiply which result in 30 - that two numbers are -6 and -5

`\displaystyle{(t-6)(t-5)=0}`

Solve like a linear equation

`\displaystyle{t=5,6}`

Therefore, the solutions to the equation are t = 5, 6