Question

Find the location of the CM of a system of three particles arranged such that two of the particles with mass m are separated by distance I along the y-axis. The third mass 2m lies on the x-axis and is separated by a distance I from one of the masses. ​

Answer 1

CM of a system ( 0.5l , 0.25l )

Step-by-step explanation:

x = (m1.x1 +m2.x2 +m3.x3) / ( m1 + m2 +m3)

x = ( m x 0 + m x 0 + 2m x l ) / ( m+m+2m)

x = 2m x l / 4m

x = 0.5 l

y = (m1 x y1 +m2 x y2 +m3 x y3) / ( m1 + m2 +m3)

y = (m x 0) + m x l + 2m x 0 ) / ( m + m + 2m )

y = m x l / 4m

y = 0.25 l