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Find the equation of the line that goes through ( 0, 2 ) and ( 3, 4 ).

Select one:

a.
2x + y - 3 = 0


b.
- 2x + 3y - 6 = 0


c.
x + y - 2 = 0


d.
2x + 3y + 6 = 0

User Poliziano
by
7.3k points

1 Answer

5 votes

Answer:

Option b. -2x + 3y - 6 = 0

Explanation:

Let's look for a linear equation of the form y=mx+b, where m is the slope and b is the y-intercept (the value of y when x = 0).

Calculate the slope first. Slope is the Rise/Run of any two points on a straight line. Using the given points, (0,2) and (3,4) we find:

Rise = 4 - 2 = 2

Run = 3 - 0 = 3

Slope, m, Rise/Run = (2/3)

The equation becomes y = (2/3)x + b

To find b, enter either of the two given points.

y = (2/3)x + b

2 = (2/3)(0) + b : for point (0,2)

b = 2

The equation becomes: y = (2/3)x + 2

Reformat this to match the format of the answer options.

y = (2/3)x + 2

3y = 2x + 6 [Multiplied by 3]

3y - 2x - 6 = 0

-2x + 3y - 6 = 0 [rearrange]

This matches option b.

User Hugo Vinhal
by
7.2k points