161k views
4 votes
Find the equation of the line that goes through ( 0, 2 ) and ( 3, 4 ).

Select one:

a.
2x + y - 3 = 0


b.
- 2x + 3y - 6 = 0


c.
x + y - 2 = 0


d.
2x + 3y + 6 = 0

User Poliziano
by
7.9k points

1 Answer

5 votes

Answer:

Option b. -2x + 3y - 6 = 0

Explanation:

Let's look for a linear equation of the form y=mx+b, where m is the slope and b is the y-intercept (the value of y when x = 0).

Calculate the slope first. Slope is the Rise/Run of any two points on a straight line. Using the given points, (0,2) and (3,4) we find:

Rise = 4 - 2 = 2

Run = 3 - 0 = 3

Slope, m, Rise/Run = (2/3)

The equation becomes y = (2/3)x + b

To find b, enter either of the two given points.

y = (2/3)x + b

2 = (2/3)(0) + b : for point (0,2)

b = 2

The equation becomes: y = (2/3)x + 2

Reformat this to match the format of the answer options.

y = (2/3)x + 2

3y = 2x + 6 [Multiplied by 3]

3y - 2x - 6 = 0

-2x + 3y - 6 = 0 [rearrange]

This matches option b.

User Hugo Vinhal
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories