Question

A Ferris wheel, rotating initially at an angular speed of 0.16 rad/s, accelerates over a 8.0-s interval at a rate of 0.040 rad/s2. What is its angular speed after this 8.0-s interval?

Answer 1

0.48 rad/s

Step-by-step explanation:

We can use this equation to find the final velocity

`w_f=w_0+at`

We are given

`w_0=0.16`

`t=8.0`

`a=0.04`

Inserting those numbers into our equation gives us

`w_f=0.16+0.04*8`

Lets solve for
`w_f`.

`w_f=0.16+0.32`

`w_f=0.48`