Question

I) if y varies directly as x and inversely as the square root of z, and y = 1/6 when x = 20 and z = 6, determine y when x = 14 and z = 5

Answer 1

Answer: Since y varies directly as x and inversely as the square root of z, we can write the following equation:

y = kx/(sqrt(z)), where k is a constant.

We can find the value of k by substituting the known values into the equation. We get:

1/6 = k*20/sqrt(6)

k = 1/240

Substituting this value of k into the original equation, we get:

y = (1/240)x/(sqrt(z))

Substituting the values x = 14 and z = 5 into this equation, we get:

y = (1/240)(14)/(sqrt(5)) = 7/120 sqrt(5) ≈ 0.22

Explanation: