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Factor each polynomial completely.
a. 5a²c - 3a²d + 5b²c-3b²d
b. x^2n+ 6x^n +9

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Answers
A = (a^2 + b^2) (5c - 3d)
B = (x^n + 3)^2

Explanation for A:
1. Factor out a^2 from (5a^2c - 3a^2d). This should look like a^2 (5c - 3d).

2. Factor out b^2 from (5b^2c - 3b^d). This should look like b^2 (5c - 3d).

3. Now multiply a^2 (5c - 3d) with b^2 (5c - 3d), by factoring out (5c - 3d) and writing a^2 + b^2 in parentheses like (a^2 + b^2) (5c - 3d)

Explanation for B:
1. Factor out x^n for x^2n + 6x^n, which should look like x^n (x^n + 6).

2. Write 9 as 3^2. The equation should look like x^n (x^n + 6) + 3^2. You can notice that the equation can be factored like (x^n + 3)^2 since you can get 6x^n by
(x^n + 3) multiples by 2, x^2n by squaring if, and 9 by squaring 3.
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