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5 votes
Which equation describes a line with a slope of 2/5 that passes through (0,4)

User Meliniak
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2 Answers

4 votes

Explanation:

since we have the slope and a point, we can start with the point-slope form

y - y1 = a(x - x1)

a is the slope, (x1, y1) is the given point.

y - 4 = (2/5)(x - 0) = 2x/5

y = 2x/5 + 4

or

y = (2/5)x + 4

User UVM
by
8.4k points
5 votes

Answer: y = 2/5x + 4

Explanation:

We will write a point-slope form equation for this line, then simplify it into a slope-intercept form equation.

Given point-slope form:

➜ m is the slope

➜ (x1, y1) is the point given

y - y1 = m(x - x1)

Substitute values in:

y - (4) = (2/5)(x - (0))

Distribute 2/5:

y - 4 = 2/5x - 0

Add 4 to both sides of the equation:

y = 2/5x + 4

User Beaudinn Greve
by
8.0k points

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