Question

9 An object of mass 1.2kg is moving with a velocity of 2.0m/s when it is acted on by a force of

4.0 N. The velocity of the object increases to 5.0 m/s.
For what period of time does the force act on the object?

Answer 1

0.90 seconds

Step-by-step explanation:

Given Info:

Object of mass ⇒ 1.2 kg

Velocity of 2.0m/s when it is acted on by a force of 4.0 N

Velocity of the object Increased to 5.0 m/s

Question:

For what period of time does the force act on the object?

Solve:

We first need to know the formula:

F = ma Or F = m(v-u)/t

F = force

m = mass of an object

a = acceleration

v = Final Velocity

u = Initial Velocity

a = Acceleration

t = Time Taken

Knowing that;

Force = 4.0 N

Mass of an object = 1.2 kg

Final velocity = 5.0m/s

Initial velocity = 2.0m/s

Time taken = [t]

Now lets plug it in the formula:

F = m(v-u)/t

4.0 = 1.2(5-2)/t

t = 0.90 seconds.

Hence, period of time at which force is acted on the object is 0.90 sec.

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