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Find the value of k so that the point (1,2) lies on the locus y²-2x-ky+5=0.​

User Ere
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1 Answer

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Answer: k = 3.5

Explanation:
1. To find k, use the point (1,2) by inputting it into the equation like (2)^2-2(1) - k(2) + 5 = 0.

2. Simplify the equation by multiplying or squaring the variables with their coefficients. This should give you 4 - 2 - 2k + 5 = 0.

3. Combine like terms 4, -2, and 5. This should give you 7 - 2k = 0.

4. Subtract 7 on both sides to get the k and its coefficient alone. Now the equation becomes -2k = -7.

5. Divide -2 on both sides to get k by itself. This would simplify the equation to k = 3.5.


User Ablemike
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