Question

Determine the maximum thickness of an aluminium sheet in which a 50 mm diameter hole is to be punched, if the compressive stress in the punch is not to exceed 80 MPa.

Answer 1

Area of punch = π * (diameter/2)^2

= π * (50/2)^2

= π * 25^2

= 1962.5 mm^2

The maximum compressive stress that the punch can withstand is 80 MPa. The thickness of the aluminium sheet can then be calculated using the following equation:

Stress = Force / Area

= (Force/Area) * (Thickness/Thickness)

= (80 MPa) * (Thickness/1962.5 mm^2)

Solving for thickness, we get:

Thickness = (80 MPa * 1962.5 mm^2) / 1

= 15700 mm

= 15.7 meters

Therefore, the maximum thickness of the aluminium sheet in which a 50 mm diameter hole can be punched without exceeding a compressive stress of 80 MPa is approximately 15.7 meters.