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Y=(x+3)(x-2)(x-r) with a y int. of 24. solve for r?

User Oszkar
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Answer:

Explanation:

To solve for r, you need to first find the values of x that make y equal to 24. These values of x are called the roots of the polynomial equation y = (x+3)(x-2)(x-r).

To find the roots of the equation, you can use the quadratic formula:

x = (-b +/- sqrt(b^2 - 4ac)) / (2a)

where a, b, and c are the coefficients of the quadratic equation y = ax^2 + bx + c.

In this case, the coefficients are:

a = 1

b = -3

c = -24

Substituting these values into the quadratic formula, we get:

x = (3 +/- sqrt(9 - 96)) / 2

= (3 +/- sqrt(-87)) / 2

Since sqrt(-87) is not a real number, there are no real roots for this equation. Therefore, the value of r cannot be determined.

User Tos
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