Answer:
First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.
For:
x
=
0
(
3
⋅
0
)
+
2
y
=
6
0
+
2
y
=
6
2
y
=
6
2
y
2
=
6
2
y
=
3
or
(
0
,
3
)
For:
y
=
0
3
x
+
(
2
⋅
0
)
=
6
3
x
+
0
=
6
3
x
=
6
3
x
3
=
6
e
d
)
(
3
)
x
=
2
or
(
2
,
0
)
We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.
graph{(x^2+(y-3)^2-0.125)((x-2)^2+ y^2-0.125)(3x+2y-6)=0 [-20, 20, -10, 10]}
Now, we can shade the left side of the line. And we need to make the boundary line a dashed line because the inequality operator does not contain an "or equal to" clause.
graph{(3x+2y-6) < 0 [-20, 20, -10, 10]}
Explanation: