Question

-x^2q-2x+10=0

Using the quadratic function above, identify all the parts of the function below.
A:
B:
C:
Axis of symmetry :

Answer 1

In the quadratic function "y = -x^2q - 2x + 10", the term "-x^2q" is the coefficient of the quadratic term and is represented by the letter "A". The term "-2x" is the coefficient of the linear term and is represented by the letter "B". The constant term "10" is the coefficient of the constant term and is represented by the letter "C".

The axis of symmetry of the graph of this quadratic function is the line that divides the graph into two congruent halves. It can be found by using the formula "x = -B / 2A". In this case, the axis of symmetry is "x = -(-2) / 2(-x^2q) = x^2q / x".

So in the function "y = -x^2q - 2x + 10", the coefficient of the quadratic term is "A = -x^2q", the coefficient of the linear term is "B = -2x", the coefficient of the constant term is "C = 10", and the axis of symmetry is "x = x^2q / x".