Question

Solve systems of equations by elimination -3x-3y=3 3x+6y=9

Answer 1

Answer: x = -5, y = 4

Explanation:

Align the two equations according to their terms:

`\left \{ {{-3x-3y = 3} \atop {3x+6y = 9}} \right.`

Add the two equations. Because -3x and 3x equals zero, they can be eliminated from the equation. This results in:

`3y = 12\\y = 4`

Plug in y = 4 into the first equation:

`-3x - 3(4) = 3\\`

Solve for x:

`-3x-12 = 3\\-3x = 15\\x = -5`

Check by plugging in both x and y:

`-3(-5) - 3(4) = 3\\15 - 12 = 3\\3 = 3`

So, x = -5 and y = 4