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If 25.0 mL of 15M nitric acid is diluted to 125 mL, what is the concentration of the new solution?

User Maschina
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1 Answer

4 votes

Answer:2.5M

Step-by-step explanation:

let the number of moles = x

x/0.025L =15

x= 15*0.025 = 0.375 moles

the concentration of the new solution = moles / volume =

0.375 / (0.025+0.125) = 2.5M

User Kelvin Trinh
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8.5k points

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