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‐3 + 4(a – 3b + 2) – 5(2 – a + 3b)

User Coert Metz
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1 Answer

3 votes

Answer: 15a – 12b – 5.

Step-by-step explanation: To solve this equation, we need to distribute the constants in front of the parentheses. Doing so, we get:

-3 + 4(a – 3b + 2) – 5(2 – a + 3b)

= -3 + 4a – 12b + 8 – 10 + 15a – 15b

= (15a – 12b) + (-10 + 8) – 3

= 15a – 12b + -2 – 3

= 15a – 12b – 5

Thus, the solution to the equation is 15a – 12b – 5.

User Wrhall
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