Question

A jug containing water at 26° C while another contains water at 82°C,if a patient wish to bath with water 40°C , the ratio of the mass of hot water to that of cold water is_​

Answer 1

Answer:2:7

Step-by-step explanation:

Quantity of heat energy before mixing= Quantity of heat energy after mixing

M1. S1.T1+ M2.S2.T2= M.S3.T3

Let, .

M1 = mass of cold water

M2 = mass of hot water

S1=S2=S3=S

M=M1+M2

T1=28,T2=82,T3= 40

M1.28 + M2.82= (M1+M2)40

M1.28 + M2.82= M1 40+M2.40

M2.82 -M2.40= M2.40–M1.28

M2.42= M1. 12

M2/M1= 12/42= 2/7

Or

M2: M1= 2:7