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If x-3 is directly proportional to the square y and x=5 when y=2 find x when y=6

User Rawr
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Answer:

If x-3 is directly proportional to the square of y, then we can say that:

(x-3) = ky^2

Where k is a constant of proportionality.

If x=5 when y=2, we can substitute these values into the equation to find the value of k:

(5-3) = k(2)^2

2 = 4k

k = 0.5

Now that we have the value of k, we can use it to find the value of x when y=6:

(x-3) = (0.5)(6)^2

x-3 = 18

x = 21

So, if x is directly proportional to the square of y and x=5 when y=2, then x=21 when y=6.

User Jess Patton
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