The ratio of effusion rates of Sulphur dioxide and methane is 0.5
To calculate the rate of diffusion of gas, we use Graham's Law.
This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:
Rate of Diffusion ∝ 1 ÷ √molar mass of the gas
We are given:
Molar mass of Sulphur dioxide = 64.066 g/mol
Molar mass of methane = 16.04 g/mol
By taking their ratio, we get:
Rate of SO₂ ÷ Rate of CH₄ = √MCH₄ ÷ √MSO₂
Rate of SO₂ ÷ Rate of CH₄ = √16.04 ÷ √64.066
Rate of SO₂ ÷ Rate of CH₄ = 0.5
Hence, the ratio of rate of effusion of Sulphur dioxide and methane will be 0.5