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(a+b+c)(a-b+c)=a2+b2+c2 prove

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Answer:

There might be an error in the question, the result below should be the correct answer. It is not possible for a^2+b^2+c^2 to be the answer.

(a+b+c)(a-b+c) = a^2 +2ac - b^2 + c^2

Explanation:

(a+b+c)(a-b+c) = a^2 - ab +ac + ba - b^2 +bc + ca - cb + c^2 (expanding the two terms in brackets first)

Since ab = ba, ac = ca and bc = cb,

-ab and ba can be cancelled out

bc and -cb can be cancelled out

Hence, (a+b+c)(a-b+c) = a^2 +2ac - b^2 + c^2

This is what I have obtained through expansion, then simplification by cancelling out the common terms.

Could you help check the question again?

User Carman
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