Question

The functionf(t)=5300(0.35)^(365t) represents the change in a quantity over t years. What does the constant 0.35 reveal about the rate of change of the quantity?

Answer 1

Answer:

The constant 0.35 reveals that the function is decaying exponentially at a rate of 65% every day

Step-by-step explanation:

Given the function:

`f(t)=5300(0.35)^(365t)`

This can be written as

`f(x)=5300(1-0.65)^(365t)`

The constant 0.35 reveals that the function is decaying exponentially at a rate of 65% every day. Notice that it is compounded 365 times in a year, so it is safe to say it is compounded daily.