Answer:
-3√3
Explanation:
do the hcf method to get all the values outside
hcf of 54= 2, 3, 3, 3
hcf of 27 = 3, 3, 3
hcf of 24 = 2,2,3,3
2✓2×3×3×3 - √3,3,3 - 3√2,2,3,3
take out the common factor and multiply it with the value we have outside leave it if it doesnt have a number
2×3√2×3 - 3✓3 -3×2×3
6√6 - 3√3 - 3×2×3
6×3 - 3√3 - 3×2×3
18-18 - 3✓3
-3√3