Question

A marketing research company desires to know the mean consumption of meat per week among males over age 50. They believe that the meat consumption has a

mean of 3.5 pounds, and want to construct a 95 % confidence interval with a maximum error of 0.08 pounds. Assuming a standard deviation of 0.6 pounds, what is
the minimum number of males over age 50 they must include in their sample? Round your answer up to the next integer.

Answer 1

we get a required sample size of 122.

Explanation:

We can use the following formula to calculate the required sample size:

n = (Z * sigma / e)^2

where:

n is the required sample size

Z is the z-score corresponding to the desired confidence level (e.g. for a 95% confidence level, Z = 1.96)

sigma is the standard deviation of the population

e is the maximum error allowed

Plugging in the given values, we get:

n = (1.96 * 0.6 / 0.08)^2 = 121.6

Rounding up to the next integer, we get a required sample size of 122.