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Find the 8th term of the geometric sequence whose common ratio is 3/2 and whose first term is 6.

User TimTeaFan
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Answer:

A geometric sequence is a sequence of numbers such that the ratio of any two consecutive terms is always the same. This ratio is called the common ratio of the sequence.

In this case, the common ratio is 3/2 and the first term is 6. The nth term of a geometric sequence can be found using the formula:

a_n = a_1 * r^(n-1)

where a_n is the nth term, a_1 is the first term, and r is the common ratio.

Substituting the given values, we have:

a_8 = 6 * (3/2)^(8-1) = 6 * (3/2)^7

Calculating, we find that the 8th term is:

a_8 = 6 * (3/2)^7 = 6 * (9/2) = 27

Therefore, the 8th term is 27.

Explanation:

User Willvv
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