Question

The position
Of a body is described by S= t^3-2t + 5 find v in m/s when t=3s

Answer 1

The velocity of an object is the rate at which its position changes. It is the first derivative of the position function with respect to time.

To find the velocity at a particular time, we need to take the derivative of the position function with respect to time and then evaluate the result at that time.

The derivative of the position function, S = t^3 - 2t + 5, with respect to time is:

dS/dt = 3t^2 - 2

Therefore, the velocity at t = 3s is:

v = 3 * 3^2 - 2 = 3 * 9 - 2 = 27 - 2 = 25 m/s.