What is the area of a sector when theta=pi/12 radians and r =4

asked Dec 28, 2024 41.1k views

4 votes

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4 votes

Answer:

$(2\pi)/(3)\text{units}^2$

Explanation:

$\displaystyle A=(r^2\theta)/(2)=(4^2*(\pi)/(12))/(2)=(16\pi)/(24)=(2\pi)/(3)\text{units}^2$

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