Question

Write an equation of a line perpendicular to the line 4x-3y=15 and passes through the point (8 -5)

Answer 1

`y+5=-(3)/(4)(x-8)`

Explanation:

`4x-3y=15 \\ \\ 3y-4x=-15 \\ \\ 3y=4x-15 \\ \\ y=(4)/(3)x-5`

The slope of the given line is
`4/3`. So, the slope of the line that we need to find is
`-3/4`.

Using point-slope form, the equation is
`y+5=-(3)/(4)(x-8)`.