Question

The magnetic field in the figure is decreasing at the rate 0.6 T/s . (Figure 1) Part A What is the magnitude of the acceleration of a proton at rest at point a? Part C What is the magnitude of the acceleration of a proton at rest at point b? Part E What is the magnitude of the acceleration of a proton at rest at point c? Part G What is the magnitude of the acceleration of a proton at rest at point d?

Answer 1

The acceleration of a proton at rest at each point is 0 m/s^2.

Step-by-step explanation:

The acceleration of a proton at rest at point a can be found using the formula:

a = q * B / m

Where a is the acceleration, q is the charge of the proton, B is the magnitude of the magnetic field, and m is the mass of the proton.

Since the proton is at rest, its initial velocity is 0 m/s. Therefore, the magnitude of the acceleration is 0 m/s2.

Similarly, at points b, c, and d, since the proton is at rest, the magnitude of the acceleration is also 0 m/s2.