Answer:
To solve this system of equations using substitution, we first need to solve one of the equations for one of the variables in terms of the other.
Let's solve the first equation for x:
6x - 5y = 10
x = (10 + 5y)/6
Now let's substitute this expression for x into the second equation:
x - 3y = -20
(10 + 5y)/6 - 3y = -20
10/6 + 5y/6 - 3y = -20
(10/6 - 3y) + (5y/6) = -20
(10 - 3y)/6 + 5y/6 = -20
10/6 - 3y/6 + 5y/6 = -20
(-3y + 5y)/6 = -20
2y/6 = -20
y = -10
Now that we have found the value of y, we can substitute it back into one of the original equations to find the value of x. Let's use the first equation:
6x - 5y = 10
6x - 5(-10) = 10
6x + 50 = 10
6x = -40
x = -40/6
x = -40/6
x = -6.666666666666667
So the solution to the system of equations is (x, y) = (-6.666666666666667, -10).