85.6k views
0 votes
Solve using identities

ii. (5x – 6) (5x – 4)

iii. (8m – 3n) (8m + 6n)

iv. (4a – 6) (4a + 6)

v. 98 × 102

vi. 104 × 103
pls give correct answer FOR ALL

User MaxGabriel
by
7.9k points

1 Answer

0 votes

Answer:

ii. (5x – 6) (5x – 4)

= 5x(5x - 4) - 6(5x - 4)

= 25x^2 - 20x - 30x + 24

= 25x^2 - 50x + 24

iii. (8m – 3n) (8m + 6n)

= 8m(8m + 6n) - 3n(8m + 6n)

= 64m^2 + 48mn - 24mn - 18n^2

= 64m^2 - 18n^2

iv. (4a – 6) (4a + 6)

= 4a(4a + 6) - 6(4a + 6)

= 16a^2 + 24a - 24a - 36

= 16a^2 - 36

v. 98 × 102

= (100 - 2)(100 + 2)

= 10000 - 400

= 9600

vi. 104 × 103

= (100 + 4)(100 + 3)

= 10000 + 300 + 400 + 12

= 10,712

Explanation:

User Croydon Dias
by
7.7k points