Answer:
line can be described by the equation y = mx + b, where m is the slope of the line and b is the y-intercept, which is the point where the line crosses the y-axis.
Since we are given that the line has a slope of 1 and includes the point (10, 10), we can plug these values into the equation to solve for the y-intercept. We get:
10 = 1 * 10 + b
b = 10 - 10
b = 0
So the equation of the line is y = x + 0, or simply y = x.
Since we are also given that the line includes the point (u, 9), we can substitute this value for y in the equation of the line to solve for u. We get:
9 = x
x = 9
Therefore, the value of u is 9.
Uday Tahlan
line that includes the points (-10, W) and (10, 6) has a slope of I. What is the value of w?
Can someone please help me?
Thank you!
To find the value of W, we can use the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope and b is the y-intercept.
Since we are given that the line includes the points (-10, W) and (10, 6) and has a slope of I, we can use these two points to find the value of W.
First, we can plug in the coordinates of one of the points and the value of the slope into the equation to solve for the y-intercept. Let's use the point (10, 6):
6 = I * 10 + b
b = 6 - 10I
Then, we can plug the values of the slope and y-intercept into the equation and solve for W using the coordinates of the other point (-10, W):
W = I * (-10) + (6 - 10I)
= -10I + 6 - 10I
= 6 - 20I
Therefore, the value of W is 6 - 20I.