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What is the equation of a line with a slope of -1/3 and passes through the point (3,-12)

User Joksnet
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1 Answer

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Answer:

y = -1/3x - 11

Explanation:

We need to find our y-intercept. Substitute the coordinate for the x and y in slope-intercept form (y=mx+b). Your x would be 3, and your y would be -12. The equation from that is -12=-1/3(3) + b. Multiply -1/3 and 3. You'll get -12=-1+b. Add the reciprocal of -1 ( positive 1) to -12. You'll get -11=b. Now that you have your b (y-intercept), you can write it in slope-intercept form. y= -1/3x - 11

User Syncere
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