Question

The critical temperature T, the temperature at which a material becomes a super conductor is 93.0 K, -250.0 celsius and -231.1 farenheit for three substances. Which of these conductors has the highest Tc, value? Show all conversion calculations.

Answer 1

126.83 K (-231.1 farenheit)

Step-by-step explanation

The given critical temperature of the three substances are:

93.0 K, -250.0 celsius and -231.1 farenheit.

To know which of these conductors has the highest Tc, value, you need to convert the given critical temperatures to kelvin

Conversion of -350.0 celsius to kelvin.

From celsius to kelvin, add 273 K, that is

`\begin{gathered} 0^0C+273=273K^{} \\ \text{Therefore,} \\ -250.0\text{ celsius }=-250.0+273=23.0K \end{gathered}`

Conversion of -231.1 farenheit to kelvin.

From farenheit to kelvin, use the conversion formula below:

`\begin{gathered} (5)/(9)(^0F-32)+273=K \\ \text{Hence, } \\ -231.1\text{ farenheit }=(5)/(9)(-231.1-32)+273 \\ =(5)/(9)(-263.1)+273 \\ =-146.17+273 \\ =126.83K \end{gathered}`

So, the critical temperature of the three substances in kelvin are:

93.0 K, 23.0 K and 126.83 K.

Hence, the conductors that has the highest Tc, value is 126.83 K (-231.1 farenheit).