Question

A solar cell is designed to have a non-reflective coating of a transparent material whose index of refraction is 1.15. What minimum thickness of the film, in nm, for light with a wavelength of 410.74 nm?

Answer 1

`\begin{equation*} 8.93*10^(-8)m \end{equation*}`

Step-by-step explanation

Parameters given:

Refractive index, n = 1.15

Wavelength of the light, λ = 410.74 nm

To find the minimum thickness of the non-reflective coating, apply the formula:

`t_(min)=(\lambda)/(4n)`

Therefore, the minimum thickness of the non-reflective coating is:

`\begin{gathered} t_(min)=(410.74*10^(-9))/(4*1.15) \\ \\ t_(min)=8.93*10^(-8)m \end{gathered}`

That is the answer.