Question

An ideal gas occupies a volume of 0.50 liter (L) at a pressure of 0.20 atmosphere. What volume will the gas occupy at 0.40

atmosphere if the temperature remains constant?

A) 0.25 L
B) 0.50 L
C) I L
D) 2L

Correct answer is 0.25, but please show the work

Answer 1

To find the volume of the gas at a pressure of 0.40 atm if the temperature is held constant, we can use the ideal gas law:

PV = nRT

Where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature of the gas.

Since the number of moles and the temperature of the gas are constant, we can rearrange the equation to solve for V:

V = (nRT)/P

Plugging in the given values, we have:

V = (nRT)/P = (nRT)/(0.40 atm)

We know that the original volume of the gas was 0.50 L, so the new volume will be:

V = (0.50 L)(0.20 atm)/(0.40 atm) = 0.50 L / 2 = 0.25 L

So the volume of the gas at a pressure of 0.40 atm will be 0.25 L. The correct answer is A) 0.25 L.

Answer 2

A) 0.25 L

Explanation:

Use Boyle's Law:

`P_1V_1 = P_2V_2`

`0.20~atm * 0.5~L = 0.40~atm * V_2`

`V_2 = (0.20~atm * 0.5~L)/(0.40~atm)`

`V_2 = 0.25~L`