Answer:
80 cm
Explanation:
You want a function of the length of the perimeter belt around three packed circles of radius 10 cm.
Perimeter
Examination of the attached figure shows the length of the belt is the sum of the lengths of the sides of an equilateral triangle with sides 20 cm, and the circumference of a circle with diameter 20 cm.
triangle perimeter = 3s = 3(20 cm) = 60 cm
circle circumference = πd = π(20 cm) = 20π cm
The length of the belt is the sum of these, or
60 cm +20π cm = (60 +20π) cm
Function
Compared to (a +bπ) cm, we find a=60, and b=20. The desired sum is ...
a +b = 60 +20 = 80
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Additional comment
You will notice that equilateral triangle PQR in the attached figure has side lengths that are twice the radius of the circle. The straight segments AB, A'B', A"B" are parallel to the triangle sides, and are the same length. (ABPR is a rectangle.)
Each circular arc, BA', for example, is 1/3 of the circumference of the circle, so the total length of all the arcs is the circumference of one 20 cm circle.