Question

is submerged to a depth of 220 m in the ocean. The surface temperature is 25oC, and the temperature 220 m down is 5.0oC. The density of seawater is 1025 kg/m3. How high does the seawater rise in the bell when it is submerged

Answer 1

2200 m (the volume of the displaced seawater multiplied by the density of seawater).

Step-by-step explanation:

The volume of the displaced water can be calculated using the formula V = (d*A), where V is the volume, d is the depth, and A is the area of the bell. Therefore, V = (220 m * A). The amount of water that has to rise in the bell is then equal to the mass of the displaced seawater, which can be calculated using the formula m = (d*A*ρ), where ρ is the density of seawater. Therefore, m = (220 m*A*1025 kg/m3). Finally, the height of the seawater in the bell can be calculated using the equation h = (m/ρ), which gives h = (2200 m).