Question

Use the quadratic formula to find the complex solutions to the equation 10x²-x+9

= 0.
=
OA)
OB)
OD)
X =
-1+√359i
20
-1± √359i
20
1± √359/
2
1± √359/
20

Answer 1

`x = (1 +√(359)i )/(20) , x = (1 -√(359)i )/(20)`

Explanation:

Given equation is

`10x^2 - x + 9 = 0`

The standard Solution of a quadratic equation is:

`x = (-b +- √(b^2 - 4ac) )/(2a)`

given a = 10, b = -1, c = 9, so

`x = (1 +- √((-1)^2 - 4*10*9) )/(20)\\x = (1 +- √(1 - 360) )/(20)\\x = (1 +- √(-359) )/(20)`

So roots are:

`x = (1 +√(359)i )/(20) , x = (1 -√(359)i )/(20)`