Question

The straight line has equation y=5x+6

Find an equation of the straight line perpendicular to L which passes through (-2,5)

Answer 1

y = -0.2x + 4.6

Explanation:

We can set up a point-slope form to calculate for the equation:

y - y1 = m (x - x1)

Before we plug the coordinate into the formula, we need m, the slope of L, we know that L is perpendicular to the straight line, and the slope of the straight line is 5:

Perpendicular slope form is: opposite reciprocal of m, which is:

-1/5 or -0.2

Now we plug all the numbers into the previous equation:

y - 5 = -0.2 (x + 2)

y = -0.2 (x + 2) + 5

y = -0.2x + -0.4 + 5

y = -0.2x + 4.6

Now this is a slope-intercept form.